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LESSON PLAN in Exothermic & Endothermic, Hess's Law, Enthalpy. Last updated October 03, 2024.
Summary
In this lesson, students learn about the concepts of Hess's Law and how to solve problems involving them.
Grade Level
High school
AP Chemistry Curriculum Framework
This lesson supports the following unit, topic, and learning objectives:
- Unit 6: Thermochemistry
- Topic 6.9: Hess’s Law
- 6.9.A: Represent a chemical or physical process as a sequence of steps.
- 6.9.B: Explain the relationship between the enthalpy of a chemical or physical process and the sum of the enthalpies of the individual steps.
- Topic 6.9: Hess’s Law
Objectives
By the end of this lesson, students should be able to
- Understand the concepts behind Hess’s Law.
- Be able to solve problems using Hess’s Law.
Chemistry Topics
This lesson supports students’ understanding of
- Hess’s Law
- Enthalpy
Time
Teacher Preparation: 10 minutes
Lesson: 30 minutes
Materials
- PowerPoint
Safety
- No specific safety precautions need to be observed for this activity.
Teacher Notes
- Students get really involved in this lesson because they view each reaction set as if it were a puzzle.
- Included in the downloads section is an accompanying worksheet (and answer key) with six problems for students to practice what they’ve learned from the lesson.
- *Note that the associated PowerPoint Presentation is animated. It is designed so that the examples are easy to follow, in a step-by-step format for the students to easily understand. If you use the PDF version, the final answers for each example will only be shown.
For the Student
Directions: Using Hess’s law, indicate on the line what change is made to the equation and rewrite each equation to find the H for each given reaction. (An answer key is provided in the downloads section.)
- Calculate the DH for the reaction: 2 Al(s) +Fe2O3(s) → 2 Fe(s)+ Al2O3(s)
Given the following information:
______2 Al(s)+3/2 O2(g) → Al2O3(s ) ΔH = -1670 kJ/mol
______2 Fe(s)+3/2 O2(g)→Fe2O3(s) ΔH = -824 kJ/mol
- Determine the DH for the reaction: NO(g)+½ O2(g) → NO2(g)
Given the following information:
______½ N2(g)+½ O2(g) → NO(g) ΔH = +90.0 kJ/mol
______½ N2(g)+O2(g) → NO2(g) ΔH = +34.0 kJ/mol
- Calculate the DH for the reaction: Cu(s) + ½ O2(g) → CuO(s)
Given the following information:
______ CuO(s) + Cu(s) → Cu2O(s) ΔH = -11 kJ/mol
______ 2 CuO(s) → Cu2O(s) + ½ O2(g) ΔH = +115 kJ/mol
- Calculate the DH for the reaction: PbCl2(s) + Cl2(g) → PbCl4(l)
Given the following information:
______ Pb(s) + 2 Cl2(g) → PbCl4(l) ΔH = -393 kJ/mol
______ Pb(s) + Cl2(g) → PbCl2(s) ΔH = -359 kJ/mol
- Calculate the ΔH for the reaction: 2 H2O2(l) → 2 H2O(l) + O2(g)
Given the following information:
______ H2(g) + O2(g) → H2O2(l) ΔH = -188 kJ/mol
______ H2(g) + ½ O2(g) → H2O(l) ΔH = -286 kJ/mol
- Calculate the ΔH for the reaction: N2(g) + O2(g) → 2 NO (g)
Given the following information:
______ 4 NH3(g) + 3 O2(g) → 2 N2(g) + 6 H2O(l) ΔH = -1530 kJ/mol
______ 4 NH3(g) + 5 O2(g) → 4 NO(g) + 6 H2O(l) ΔH = -1170 kJ/mol